Still looking for answers here ....
At OSH I asked Bob about Patrol engine position. The 2005 Bearhawk
Newsletter gives a figure of 56" to 58" as the recommended
datum/prop-flange distance. Bob said to use the 58" figure if I intended haul heavy rear loads.
The Newsletter specs that CG should be in the range of 12.8" to 20" behind datum.
The newsletter sample weight/balance sheet for N289R (which I assume is for the O-360) is with metal prop and no electrical system.
I have an O-320 and hope to license it at 1320# so will probably use a wooden prop.
So if I save about 13# in prop-wt and lets say that the bare 0-320 is 20# lighter than the O-360, I should be about 33# lighter. Lets say
the 360 engine with prop is 300# and my engine with prop is 267#.
Let us also say that the actual aircraft CG we are shooting for is 16" behind datum and that the 56" datum/prop-flange figure was used on N289R. Let us also say that the actual center of gravity for the engine/prop combination (ECG) is somewhere in the middle of the engine; say 10" behind the prop-flange. This would give the actual moment contribution of the O-360 engine/prop combination as:
303# x (CG to ECG distance) = 303 x (56 + 16 -10) = 303 x 62 = 18786 inch-pounds
Now if I use a lighter engine and a lighter prop, but want the same weight/balance contribution for my aircraft, I want my O-320 positioned such that it balances the rest of the aircraft with an equivalent 18786 inch-pound moment.
Since my engine-prop combo weighs only 267#, I can now calculate its preferred position
My CG to ECG distance for my O-320 should be 18786/267 = 70"
Again assume that my engine-prop combo has ECG 10" behind the prop-flange and that desired aircraft CG is 16" behind datum. My O-320 position can be calculated as follows.
Location of O-320 prop-flange = (70 -16 + 10) = 66" in front of datum
Now this 66" figure seems really excessive, a full 8" in front the 58" max recommended in the Newsletter.
I must be doing something wrong, but I don't know what.
Bergy, I think your numbers are about right. I ran the numbers and thought I would show my work and expose it in the public domain for critical feedback.
I think 1) your target is a CG at 16 inches aft of the datum and 2) you are trying to understand how your O-320 with 33 pounds less weight will effect the empty weight CG. 3) you want to know how far you have to adjust your engine mount to have the same CG with a light engine/prop.
If you have a 1000 pound airplane and move its 300 pound engine forward 2 inches it would shift the CG .6 inches. (Formula for change in CG caused by shifting weight .....
Change in CG = (Weight Shifted x Distance weight is shifted) / Total Weight. So, (300 pounds x 2 inches) / 1000 pounds = 600 inch pounds / 1000 pounds = .6 inches
If you removed 33 pounds from a station that is 56 inches
ahead of the Datum (Leading edge) of a 1000 pound airplane with an empty weight CG of 10.0 inches
aft of datum, it will shift the CG 2.23" aft. (Formula for adding weight....
Change in CG = (Weight added x distance between Old CG and the Weight) / New Total Weight. So, we are removing 33 pounds that is 66 inches in front of the empty weight CG. The math looks like (-33 pounds x -66 inches) / (1000 pounds - 33 pounds) = 2178 in lbs / 963 lbs. = 2.26 inches.
If you want to remove a 300 pound engine @ -56 " aft of datum from a 1000 pound airplane with an empty weight CG of 10.0 aft of datum, then you will have a 700 pound airframe with a CG of 38.3" aft of datum.
Weight x Arm = Moment
1000 lb x 10 in = 10,000 in lb
-300 lb x -56 in = 16,800 in lb
+700 lb x __ in = 26,800 in lb
The new empty weight CG is 26800 in lbs / 700 lbs = 38.3 inch empty weight CG.
If I add a 263 pound engine to the 700 pound airframe, and want the CG to remain at 10.0 inches aft of Datum that I had before, I need to put that engine then it looks something like this.
Weight x Arm = Moment
700 lb x 38.3 in = 26,800 in lbs Empty weight of airframe w/o engine
263 lb x ___ in = _____ in lbs
963 lb x 10.0 in = 9,630 in lbs Emtpy weight/cg of airframe that I desire
So, it looks like we need a moment for the engine to be 26800 - 9630 = -17,170 in lbs.
-17,170 in lbs / 263 lb engine is 65.28 inches in front of the datum
700 lb x 38.30 in = 26,800 empty weight
263 lb x -65.28 in = -17,170 in lb
963 lb x 10.00 in = 09,630 in lb
So. the old engine was sitting at 56 inches, and new one is at 65 1/4". You came up with 66